Question

What is the change of energy where the wavelength is 4078 A

Answer 1

The change of energy : 4.8744 x 10⁺¹⁹ J

Further explanation

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

`\large{\boxed{\bold{E\:=\:h\:.\:f}}}`

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

f = c / λ

c = speed of light

= 3.10⁸

λ = wavelength

The wavelength is 4078 A = 4.078 x 10⁺⁷ m

`\tt E=h.(c)/(\lambda)\\\\E=6.626* 10^(-34)* (3.10^8)/(4.078* 10^(-7))\\\\E=4.8744* 10^(-19)~J`