Register

The expansion of (1 + px +qx2)8 is 1 + 8x + 52x² + kx³+... . Calculate the values of p, q and k. Ans: [p = 1, q=3, k = 224] how do i do this question? It’s binomial theorem.

The expansion of (1 + px +qx2)8 is 1 + 8x + 52x² + kx³+... . Calculate the values of p, q and k. Ans: [p = 1, q=3, k = 224] how do i do this question? It’s binomial theorem.
40.2k views
23 votes
The expansion of (1 + px +qx2)8 is 1 + 8x + 52x² + kx³+... . Calculate the values of p, q and k.

Ans:
[p = 1, q=3, k = 224]


how do i do this question? It’s binomial theorem.

User Cascadox
by
7.8k points

1 Answer

13 votes

Answer:

i think you have to multiply

Explanation:

User Madelynn
by
7.8k points
← Prev Question Next Question →

Related questions

User Suzumakes
asked Jun 28, 2024 76.1k views
3. When kx³ + x² - 5x -5 is divided by x + 1, its remainder is 0. Hence, the value of k is?​​
Suzumakes asked Jun 28, 2024
by Suzumakes
7.9k points
1 answer
1 vote
76.1k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!