Question

What is the equation of the line that passes through the point (-3,1) and is parallel to y= -½ + 3

Answer 1

Explanation:

Parallel lines are lines whose slopes are the same

We are given the line
`y = (-1)/(2)x + 3`

so the other line's slope has to be
`(-1)/(2)`

We can use y = mx + b to find the equation of the line

`y = mx + b\\y = (-1)/(2)(x)+b\\1 = (-1)/(2)(-3)+b\\1 = (3)/(2) + b\\b = (-1)/(2)`

so

`y = (-1)/(2)(x) - (1)/(2)`