Answer:
Student correctly measures the ΔT.
Q = 113.52 J
Step-by-step explanation:
Given data:
Mass of gold is = 10.0 g
Initial temperature = T1 = 135°C
Final temperature = T2 = 47°C
ΔT = 88°C
Does ΔT is correct = ?
Solution:
Student is calculating the amount of heat released by gold.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of gold is 0.129 J/g.°C
ΔT = T2 - T1
ΔT = 47°C - 135°C
ΔT = -88°C
Student correctly measures the ΔT.
We can calculate the heat released by gold.
Q = 10.0 g× 0.129J/g.°C ×88°C
Q = 113.52 J