Question

I need the answer asap plz!!

A sample of water vapor has a pressure of 36.0 Pa and a temperature of 300.0 K. If the pressure is
reduced to 32.0 Pa, what will the new temperature be?

Answer 1

266.67 K

Step-by-step explanation:

Recall the formula for ideal gasses:

P * V = n * R * T

from which a proportion can be obtained if the volume of the gas and its number of moles remain constant. This is:

T / P = constant and therefore T1 / P1 = T2/ P2

Then for our case:

300 / 36 = T2 / 32

solving for T2:

T2 = 300 * 32 / 36 = 266.67 K