Question

Pls answer Both questions

Answer 1

`-(1)/(2)ab^(12)`

`(w^(10))/(3y^(4))}`

Explanation:

`(-2a^2b^4)/(4ab^(-8)) =`

`= (-2)/(4)a^(2-1)b^(4-(-8))`

`= -(1)/(2)ab^(12)`

`(-5w^4y^(-2))/(-15w^(-6)y^(2)) =`

`= (-5)/(-15)w^(4 - (-6)) y^(-2 - 2)`

`= (1)/(3)w^(10) y^(-4)`

`= (w^(10))/(3y^(4))`