Question

a 90 gram object moves around a circle whose diameter is 2.56 m at a constant speed off 16 m/s. what is the object acceleration? how much time will take to complete the around?

Answer 1

`a=200\ m/s^2` and t = 0.5 s

Step-by-step explanation:

Given that,

Mass of the object, m = 90 gram = 0.09 kg

Diameter of the circle, d = 2.56 m

Radius, r = 1.28 m

Speed, v = 16 m/s

We need to find the object acceleration. On the circular path, acceleration is given by :

`a=(v^2)/(r)\\\\a=((16)^2)/(1.28)\\\\a=200\ m/s^2`

So, the object's acceleration is
`200\ m/s^2`.

Let t is time it will take to complete the around. Speed is given by :

`v=(2\pi r)/(t)\\\\t=(2\pi r)/(v)\\\\t=(2\pi * 1.28)/(16)\\\\t=0.5\ s`

So, time to cover one complete round is 0.5 s.