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Amzol thinks that (x+5)^2=x^2+25 for all values of x. Is Amzol right?

Amzol thinks that (x+5)^2=x^2+25 for all values of x. Is Amzol right?
81.5k views
2 votes
Amzol thinks that (x+5)^2=x^2+25 for all values of x.
Is Amzol right?

User Jennifer Shehane
by
9.2k points

1 Answer

4 votes

Answer:

The answer is x=0 so probably he is

Explanation:

User Manjabes
by
8.7k points
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