Answer:
6 possible values of squares that she can move.
Explanation:
In these events, as given
Doris
- rolls 3 standard dice(s) (or is it die, dies?))
- two of them land on 4 and 3
-Find how many possible squares can she move
So, it is already known that Doris has to move 7 squares (because 3 + 4 = 7), yet she has another 6 sets of possibilities because a dice has 6 facets.
Hence she has 6 different possible numbers of squares she can move.
The possibilities are:
-8 squares (if she rolls a 1)
-9 squares (if she rolls a 2)
-10 squares (if she rolls a 3)
-11 squares (if she rolls a 4)
-12 squares (if she rolls a 5)
-13 squares (if she rolls a 6)