Answer:
![(x+2)(x-2)(x+1)(x-1)](https://img.qammunity.org/2021/formulas/mathematics/college/qf3qo79ivakz153rad4vjay7d9crwmi5z8.png)
Explanation:
We want to factor the expression
.
First, notice that this is in quadratic form. In other words, both the exponents have even power.
Therefore, we can make a substitution to simplify the expression.
So, let’s let
.
Our expression is the same as:
![(x^2)^2-5(x^2)+4](https://img.qammunity.org/2021/formulas/mathematics/college/hsb7ayggazp4c79jida708e1ixk6orpkjl.png)
Substitute:
![u^2-5u+4](https://img.qammunity.org/2021/formulas/mathematics/college/7629had15nswe53uxrctkd9pea2ap3hmt7.png)
Now, we can factor like normal. We can use -1 and -4. Therefore:
![=(u-4)(u-1)](https://img.qammunity.org/2021/formulas/mathematics/college/ms2lbwxrxi1b2yy6wjubf86rvdv10wcscd.png)
We can now substitute back u:
![=(x^2-4)(x^2-1)](https://img.qammunity.org/2021/formulas/mathematics/college/r3kddvrcd8uv1m12l9qw5iq12y670hi5b8.png)
Both of these can be factored furthered using the difference of two squares:
![(a^2-b^2)=(a+b)(a-b)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/k0y5fx77zm7d7ui8wdj66i0rw8ig057fzw.png)
Therefore, we will have:
![=(x+2)(x-2)(x+1)(x-1)](https://img.qammunity.org/2021/formulas/mathematics/college/dab81rvvfsh9y6bii4jduxwpv36p2abyx2.png)
And we are done!