Question

X^2-6x+5=0 solve with quadratic formula

Answer 1

x = 5 and 1

Explanation:

`x^2-6x+5=0\\x_(1,\:2)=(-\left(-6\right)\pm √(\left(-6\right)^2-4\cdot \:1\cdot \:5))/(2\cdot \:1)\\x_(1,\:2)=(-\left(-6\right)\pm \:4)/(2\cdot \:1)\\\rightarrow x_1=(-\left(-6\right)+4)/(2\cdot \:1),\:x_2=(-\left(-6\right)-4)/(2\cdot \:1)\\\\(-\left(-6\right)+4)/(2\cdot \:1)\\\\=(6+4)/(2\cdot \:1)\\\\=(10)/(2\cdot \:1)\\\\=(10)/(2)\\\\=5\\\\\\(-\left(-6\right)-4)/(2\cdot \:1)\\\\=(6-4)/(2\cdot \:1)\\\\=(2)/(2\cdot \:1)\\\\=(2)/(2)\\\\=1`

Answer 2

Answer: x1 = 5

x2 = 1

Explanation:

1. Identify the coefficients

2. Move the constant to the right side of the equation and combine

3. Complete the square

4. Solve for x