187k views
3 votes
Write an equation of the line passing through the points (3,1) and (−1, −7) PLS HELP ASAP

User Ziewvater
by
8.4k points

1 Answer

4 votes

Answer:


y=2x-5

Explanation:

Find the slope using the two points:


(y_(2)-y_(1))/(x_(2)-x_(2))=slope

Insert the coordinate points:


(3_(x1),1_(y1))\\\\(-1_(x2),-7_(y2))\\\\(-7-1)/(-1-3)

Simplify:


(-7-1)/(-1-3) =(-8)/(-4) =2

The slope is 2.

Now write an equation using point-slope form:


y-y_(1)=m(x-x_(1))

  • m is the slope
  • x and y are the corresponding coordinate points

Insert:


(3_(x1),1_(y1))\\\\y-1=2(x-3)

Simplify and convert to slope-intercept form:


y=mx+b

  • m is the slope
  • b is the y-intercept
  • x and y are the corresponding coordinate points

Use the distributive property:


y-1=2(x)+2(-3)\\\\y-1=2x-6

Add 1 to both sides:


y-1+1=2x-6+1\\\\y=2x-5

:Done

User Ljrk
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories