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Write an equation of the line passing through the points (3,1) and (−1, −7) PLS HELP ASAP

User Ziewvater
by
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1 Answer

4 votes

Answer:


y=2x-5

Explanation:

Find the slope using the two points:


(y_(2)-y_(1))/(x_(2)-x_(2))=slope

Insert the coordinate points:


(3_(x1),1_(y1))\\\\(-1_(x2),-7_(y2))\\\\(-7-1)/(-1-3)

Simplify:


(-7-1)/(-1-3) =(-8)/(-4) =2

The slope is 2.

Now write an equation using point-slope form:


y-y_(1)=m(x-x_(1))

  • m is the slope
  • x and y are the corresponding coordinate points

Insert:


(3_(x1),1_(y1))\\\\y-1=2(x-3)

Simplify and convert to slope-intercept form:


y=mx+b

  • m is the slope
  • b is the y-intercept
  • x and y are the corresponding coordinate points

Use the distributive property:


y-1=2(x)+2(-3)\\\\y-1=2x-6

Add 1 to both sides:


y-1+1=2x-6+1\\\\y=2x-5

:Done

User Ljrk
by
8.5k points