Question

What is the solution to this system of equations? -3x+2y=3 y+2z=0 x-y-z=-1

Answer 1

The solution is B, (x, y, z) = (-1, 0, 0).

Eliminate z from the last two equations:

(y + 2z) + 2 (x - y - z) = 0 + 2 (-1)

2x - y = -2

Eliminate y from this and the first equation:

(-3x + 2y) + 2 (2x - y) = 3 + 2 (-2)

x = -1

Solve for y :

2x - y = -2

2 (-1) - y = -2

y = 0

Solve for z :

x - y - z = -1

-1 - 0 - z = -1

z = 0