Question

How many grams of aluminum chloride can be produced from 7.32g of ammonium perchlorate?

Answer 1

2.77g of
`AlCl_(3)` can be produced.

Step-by-step explanation:

Use stoichiometry.

Balanced equation:
`3Al + 3NH_(4) ClO_(4)` ⇒
`Al_(2) O_(3) + AlCl_(3) +3NO + 6H_(2) O`

`NH_(4) ClO_(4) : AlCl_(3)`

3 : 1 **
`n=(m)/(M)`

0.0623** :
`x`
`n=(7.32)/(117.49)` = 0.0623

`3x=0.0623\\x=0.020767`

`n=(m)/(M)`

`m=nM`

m= (0.020767)(133.34)

m= 2.77g