Question

A 9mm bullet has a mass of 0.007 kg. When fired

from a handgun, its momentum is measured to
be 2.66 kgm/s. What is the velocity of the bullet?

Answer 1

The velocity of the 9mm bullet, with a mass of 0.007 kg and momentum of 2.66 kgm/s, is calculated as 380 meters per second by dividing the momentum by the mass.

The velocity of a bullet can be calculated using the known momentum and mass of the bullet.

Momentum (ℒ) is the product of mass (m) and velocity (v), as given by the equation ℒ = m v.

To find the velocity of a 9mm bullet with a mass of 0.007 kg and a measured momentum of 2.66 kgm/s, the equation must be rearranged to solve for velocity (v = ℒ / m).

Velocity (v) = Momentum (ℒ) / Mass (m) = 2.66 kgm/s / 0.007 kg = 380 m/s.

The bullet's velocity is therefore 380 meters per second.

Answer 2

The velocity of the bullet is 380 m/s

Step-by-step explanation:

The given parameters are;

The mass of the 9 mm bullet fired = 0.007 kg

The measure of the momentum the bullet has = 2.66 kg·m/s

The equation for linear momentum is given as follows;

The linear momentum of an object = The mass of the object × The velocity of the object

∴ The velocity of the object = The linear momentum of an object/(The mass of the object)

The velocity of the bullet = The linear momentum of an bullet/(The mass of the bullet)

The velocity of the bullet = 2.66 kg·m/s/(0.007 kg) = 380 m/s

The velocity of the bullet = 380 m/s.