Question

At what height from the surface of earth will the value of 'g' reduced to 64% from the value at the surface? Radius of earth = 6400 Km​

Answer 1

Answer: 1600 km from the surface

Step-by-step explanation:

`E = (GM)/(R^(2) )\\g1 = (GM)/(R1^(2) ) \\R1 = 6400 km\\g2 = 0.64g1\\(g1)/(g2) = ((GM)/(R1^(2) ) )/((GM)/(R2^(2) ) ) \\(g1)/(0.64g1) = (R2^(2))/(R1^(2) )\\(1)/(0.64) = (R2^(2))/(6400^(2) )\\\\(1)/(0.8) = (R2)/(6400)\\\\R2 = (6400)/(0.8)\\R2 = 8000 km\\`

Therefore, 8000 km - 6400 km = 1600 km from the surface