Answer:
The horizontal distance traveled by the rocket is 90.46 m
Step-by-step explanation:
Given;
initial velocity of the rocket, u = 30 m/s
angle of projection, θ = 40°
the horizontal distance traveled by the rocket = ?
The horizontal distance traveled by the rocket is given by the range of the projectile.
The range of the projectile is given as;
![R = (u^2Sin(2\theta))/(g)\\\\R = ((30)^2sin(80^0))/(9.8)\\\\R = 90.46 \ m](https://img.qammunity.org/2021/formulas/physics/college/nq9nelfszc3zmb4imqz4hfddk1g7vmryoc.png)
Therefore, the horizontal distance traveled by the rocket is 90.46 m
The closest answer in the given options is 90.54 m