Answer: Selling price of each corsage = $ 23
Selling price of each boutonniere = $26
Explanation:
Let x =Selling price of each corsage.
y = Selling price of each boutonniere.
As per given, we have
![18x+21y= 960\ \ \ \ (i)\\\\ 25x+17y= 1017\ \ \ \ (ii)](https://img.qammunity.org/2021/formulas/mathematics/high-school/718tngng71w7shyb91zd424ld4ckai2p9t.png)
Divide (i) by 3, we get
![6x+7y=320\\\\\Rightarrow\ 6x=320-7y\\\\\Rightarrow\ x=(320-7y)/(6)\ \ \ \ (iii)](https://img.qammunity.org/2021/formulas/mathematics/high-school/m92gbru8g9gkioxjzaty8w2bsbmecjpew3.png)
Put this in (ii) , we get
![25((320-7y)/(6))+17y=1017\\\\\Rightarrow\ (25(320)-25(7y))/(6)+(17*6y)/(6)=1017\\\\\Rightarrow\ (8000-175y)/(6)+(102y)/(6)=1017\\\\\Rightarrow\ (8000-175y+102y)/(6)=1017\\\\\Rightarrow\ 8000-73y=6*1017\\\\\Rightarrow\ 8000-73y=6102\\\\\Rightarrow\ 73y=8000-6102\\\\\Rightarrow\ 73y= 1898\\\\\Rightarrow\ y=(1898)/(73)\\\\\Rightarrow\ y=26](https://img.qammunity.org/2021/formulas/mathematics/high-school/9kn241bfcihqsuta425i5fyze79dfai9us.png)
Put this in (iii),
![x=(320-7(26))/(6)=23](https://img.qammunity.org/2021/formulas/mathematics/high-school/kf0b0q898j28s98wxa1v57s5wugz429xv6.png)
Hence, Selling price of each corsage = $ 23
Selling price of each boutonniere = $26