Question

A tennis ball was thrown straight up with initial velocity of 22.5 m/s. How high does the ball rise

taking into consideration that upward acceleration due to gravity is -9.81m/s ?

Answer 1

4.6 s

Step-by-step explanation:

Answer 2

`h_m=25.8\ m`

Step-by-step explanation:

Vertical Launch Upwards

In a vertical launch upwards, an object is launched vertically up without taking into consideration friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

`\displaystyle h_m=(v_o^2)/(2g)`

The tennis ball was thrown straight up with a speed of v0=22.5 m/s. The acceleration of gravity is g=9.81\ m/s^2, thus:

`\displaystyle h_m=(22.5^2)/(2\cdot 9.81)`

`\mathbf{h_m=25.8\ m}`