Question

A 0.28-kg stone is thrown vertically into the air, rising to a height of 4.3 meters. What was the magnitude of the impulse it received from the person tossing the stone

Answer 1

The impulse it received from the person tossing the stone is 2.58 N.s

Step-by-step explanation:

Given;

mass of the stone, m = 0.28 kg

height risen by the stone in air, h = 4.3 meters

Time taken for the stone to reach 4.3 meters is given by;

`t = \sqrt{(2h)/(g) }\\\\t = \sqrt{(2*4.3)/(9.8)}\\\\t = 0.94 \ s`

Impulse is given as;

J = Ft

where;

force applied on the stone due to its weight

J = (mg)t

J = (0.28 x 9.8)(0.94)

J = 2.58 N.s

Therefore, the impulse it received from the person tossing the stone is 2.58 N.s