Answer:
1/4
Step-by-step explanation:
Let the earlobe allele be represented by A. since the attached earlobe is the recessive trait, the genotype would be aa while the free earlobe would be AA. The heterozygous condition would be Aa.
Two individuals heterozygous for free earlobes mated:
Aa x Aa
AA Aa Aa aa
AA and Aa = Free earlobe = 3/4
aa = attached earlobe = 1/4
Hence, the probability of the couple having a child with an attached earlobe is 1/4.