Question

a radioactive substance decays to 1/3 of its original amount in 10 hours. Find the half life of the substance g

Answer 1

Step-by-step explanation:

`N=N_0((1)/(2) )^(t)/(T)` , T is half life , t is time taken to reduce N₀ to N .

1/3 =
`((1)/(2))^(10)/(T)`

taking log on both sides

-log3 = 10/Tx log.5

T = 10 x log .5 / - log 3

= 10 x -.3010 / - .4771

= 6.31 hours .