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League baseball team plays 122 games in a season. If the team won 14 more than three times as many games as they​ lost, how many wins and losses did the team​ have?

User Byorn
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Given:

Total number of games in a season = 122

The team won 14 more than three times as many games as they​ lost.

To find:

The number of wins and losses.

Solution:

Let the number of losses be x.

Then, according to the question

Number of wins = 3x+14

We know that,

Win + losses = Total number of games


(3x+14)+x=122


4x+14=122

Subtract 14 from both sides.


4x=122-14


4x=108

Divide both sides by 4.


x=27

Now,

Number of losses = 27

Number of wins
=3* 27+14


=81+14


=95

Therefore, the team won 95 games and they​ lost 27 games.

User Anthony Kimanzi
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