Question

A hockey puck has a coefficient of kinetic friction of μk = .35. If the puck feels a normal force (FN) of 5 N, what is the frictional force that acts on the puck?

Answer 1

The frictional force is
`F_f = 1.75 \ N`

Step-by-step explanation:

From the question we are told that

The coefficient of kinetic force is μk = 0.35

The normal force felt by the puck is
`F_N = 5 \ N`

Generally the frictional force that acts on the puck is mathematically represented as

`F_f = \mu_k * F_N`

=>
`F_f = 0.35 * 5`

=>
`F_f = 1.75 \ N`