Answer:
Pb(CH3COO)2(s) -------> Pb^2+(aq) + 2CH3COO^- (aq)
Step-by-step explanation:
Recall that a strong electrolyte is an electrolyte that dissociates completely in solution. Hence, if we say that lead(II) acetate is a strong electrolyte we are actually saying that lead(II) acetate ,dissociates completely in solution to yield lead II ions and acetate ions.
This implies that the reaction equation shown in the answer section tends to go to completion since lead(II) acetate is a strong electrolyte.