The question seems incomplete the complete question is given below
Two 3 kg bodies, A and B, collide. The velocities before the collision are A = (32 i + 41 j) m/s and B = (31 i + 3.2 j) m/s. After the collision, velocity of A = (7.9i + 11 j) m/s. What are (a) the x-component and (b) the y-component of the final velocity of B
Answer:
x- component (Vb)final = 55.1
y- component (Vb)final = 33.2
![ms^-1](https://img.qammunity.org/2021/formulas/physics/college/7wj49j2x97ty5260unz1rn7afsbgw5g8yz.png)
Step-by-step explanation:
a) On applying law of conservation of momentum
initial momentum = final momentum
for x - component we take the coefficients of i from the given data
(Ma*Va)initial + (Mb*Vb)initial = (Ma*Va)final + (Mb*Vb)final
since Ma = Mb= 3
so it will cancel out in the equation
(Va)initial + (Vb)initial = (Va)final + (Vb)final
32 + 31 = 7.9 + (Vb)final
(Vb)final = 55.1
![ms^-1](https://img.qammunity.org/2021/formulas/physics/college/7wj49j2x97ty5260unz1rn7afsbgw5g8yz.png)
b) for the y-component we take the component of j from the data.
(Ma*Va)initial + (Mb*Vb)final = (Ma*Va)final + (Mb*Vb)final
41+3.2 = 11 + (Vb)final
(Vb)final = 33.2
![ms^-1](https://img.qammunity.org/2021/formulas/physics/college/7wj49j2x97ty5260unz1rn7afsbgw5g8yz.png)