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A ball is dropped from the rest from a high window of a tall building and called for 4 seconds. Neglecting air resistance, the final velocity of the ball is ____ m/s. (g=-9.8m/s^2)

1 Answer

3 votes

Answer:

-39.2m/s

Step-by-step explanation:

Given that :

t = 4secs

g = -9.8m/s^2

v = ?

u = 0m/s ( since it was at rest )

V = u +at............. 1

Where v is the final velocity

a = -g = -9.8m/s^2 since the ball was dropped from a height which will eventually make it move against gravity

t = 4secs

Substitute the values into 1

v = 0 - 9.8×4

v = -39.2m/s

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