120,715 views
29 votes
29 votes
How many
particles would
be found in a
2.74 g sample of
Beryllium sulfide?

User Roman Dibikhin
by
2.6k points

2 Answers

16 votes
16 votes

Answer:

4.03 × 10²² particles

Step-by-step explanation:

Had the same question and got it correct.

User Georgi
by
2.7k points
20 votes
20 votes

Answer:

4.03 × 10²² particles of beryllium sulfide.

Step-by-step explanation:

The formula to find the number of particles is:

Number of particles/atoms = number of moles × (6.02 × 10²³)

6.02 × 10²³ = Avogadro's number

But first, we will have to find the number of moles. This can be found using the formula:

Number of moles = mass ÷ Mr

Mr of BeS = 9 + 32.1 = 41.1

Number of moles = 2.74 ÷ 41.1 = 0.067 mol

Now that we know the number of moles, we can find the number of particles.

Number of particles = 0.067 × 6.02 × 10²³

∴ Number of particles = 4.03 × 10²²

User Frenchcooc
by
3.2k points