Answer:
The final speed is 14 m/s and its position is 28.5 m.
Step-by-step explanation:
The question says "A mobile starts from the origin of the axle system with an initial speed of 5m / s. It moves uniformly accelerated with acceleration 3m / s2. Find out the speed and position of the mobile after a time interval of 3s "
Given that,
Initial speed, u = 5 m/s
Acceleration, a = 3 m/s²
We need to find the final speed and position of the mobile after a time interval of 3s.
For final speed (v)
It can be calculated using first equation of motion as:
v=u+at
v=5+3(3)
v = 14 m/s
Let it is at x distance. Using second equation of motion to find it as follows :
![x=ut+(1)/(2)at^2\\\\x=5(3)+(1)/(2)* 3* (3)^2\\\\x=28.5\ m](https://img.qammunity.org/2021/formulas/physics/high-school/6hh9f5xtrm3k3kxgps7lvj55vqx0sn1bim.png)
Hence, the final speed is 14 m/s and its position is 28.5 m.