Answer:
The horizontal distance traveled by the projectile is 60 m
Step-by-step explanation:
Given;
initial horizontal velocity of the projectile, Vₓ = 30 m/s
time of the motion of the projectile, t = 2 s
The horizontal distance traveled by the projectile is given by the range of the projection;
X = Vₓt
X = 30 x 2
X = 60 m
Therefore, the horizontal distance traveled by the projectile is 60 m
Therefoe