Question

The place kicker on a football team kicks a ball from ground level with an initial speed of 5.80 m/s at an angle of 17.0° above the horizontal. How long is the ball in the air before it lands on the ground again

Answer 1

0.34 s

Step-by-step explanation:

Given that,

Initial speed of a ball, u = 5.8 m/s

It is kicked at an angle of 17.0° above the horizontal.

The vertical component of velocity will be,

`u_y=u\sin\theta\\\\=5.8* \sin 17\\\\=1.69\ m/s`

Let it takes t time in the air before it lands on the ground again. It can calculated as :

`t=(2u_y)/(g)\\\\t=(2* 1.69)/(9.8)\\\\t=0.34\ s`

So, it will take 0.34 seconds.