Question

An electron is moving at 2.02.0 ×× 105m/s105 m/s in the positive y direction. The magnetic force on the electron is 3.03.0 ×× 1010−12−12 ????N in the negative-z direction. What is the magnitude and direction of the magnetic field?

Answer 1

The magnitude and direction of the magnetic field is 93.63 T in negative x direction.

Step-by-step explanation:

Given;

speed of the electron in positive y direction, v = 2.0 x 10⁵ m/s

magnetic force on the electron, F in negative z direction = 3.0 x 10⁻¹² N

The magnitude of the magnetic force is given by;

F = Qv x B

B = F / Qv

`B = (3*10^(-12))/( (1.602*10^(-19))(2*10^5))\\\\B = 93.63 \ T`

The direction of the magnetic field is is as;

Based on the direction of magnetic force (negative z direction), the charge will be directed into negative y-direction because electron is negatively charged. Thus, the direction of the magnetic field will be in the negative x-direction

`F_((-z))= Q_((-y))V* B_((-x))`

Therefore, the magnitude and direction of the magnetic field is 93.63 T in negative x direction.