Hi there!
We can use the following relationship between the Potential Difference and the Electric field:
![V = E d](https://img.qammunity.org/2023/formulas/physics/college/1j8a3tqqyyo3bvnx6zvrv0vs60a522wmh0.png)
V = Potential Difference (500V)
E = Electric Field (V/m)
d = separation between plates (0.2 m)
We can rearrange the equation to solve for the electric field:
![E = (V)/(d)\\\\](https://img.qammunity.org/2023/formulas/physics/college/d247okocww3nouam65pzgq9oj0f4uh1yt2.png)
Plug in the given values.
![E = (500)/(0.2) = \boxed{2500 (V)/(m)}](https://img.qammunity.org/2023/formulas/physics/college/dgpzx9s9fi76jip8fjl0274eclv7ti8jn2.png)