This question is incomplete, the complete question is;
A large tower is to be supported by a series of steel wires. It is estimated that the load on each wire will be 11,100 N.
Determine the minimum required wire radius assuming a factor of safety of 3 and a yield strength of 1500 MPa.
answer in mm please
Answer:
the minimum required wire radius is 5.3166 mm
Step-by-step explanation:
Given that;
Load F = 11100N
N = 3
∝y = 1500 MPa
∝workmg = ∝y / N = 1500 / 3 = 500 MPa
now stress of Wire:
∝w = F/A
500 × 10⁶ = 11100 / A
A = 22.2 × 10⁻⁶ m²
so
(π/4)d² = A
(π/4)d² = 22.2 × 10⁻⁶
d² = 2.8265 × 10⁻⁵
d = 5.3165 7 × 10⁻³ m³
now we convert to mm(millimeters)
d = 5.3166 mm
Therefore the minimum required wire radius is 5.3166 mm