Answer:
There will be left 80.4 of the sample in 500 years
Explanation:
Radioactive Decay Model
Suppose N is the size of a population of radioactive atoms at a given time t, No is the size of an initial population of radioactive atoms at time t = 0, and k is the decay constant, then the equation is as follows:
![N=N_o\cdot e^(-kt)](https://img.qammunity.org/2021/formulas/mathematics/college/8z6rnoaiwf2kn3gy3w4cjjva7buurcrlob.png)
The time required for half of the original population of radioactive atoms to decay is called the half-life Th. The relationship between the half-life and the decay constant is:
![\displaystyle T_h=(ln 2)/(k)\approx(0.693)/(k)](https://img.qammunity.org/2021/formulas/mathematics/college/nkiz9hib5xfswc5y67zrvd1re59l8hy6gl.png)
We know the half-life of radium-226 is about 1,590 years. We can find the value of k by solving the above equation:
![\displaystyle k=(ln 2)/(T_h)](https://img.qammunity.org/2021/formulas/mathematics/college/g871ouhxwex68dezjxpeh9sa3wpk7y7lqe.png)
![\displaystyle k=(ln 2)/(1,590)](https://img.qammunity.org/2021/formulas/mathematics/college/ks9vypek48nvurkr2ogn3igawzh0racdu7.png)
k=0.000436
The initial mass of the sample is 100 gr, thus the model for the mass at time t is:
![M(t)=100\cdot e^(-0.000436t)](https://img.qammunity.org/2021/formulas/mathematics/college/gyaxl8ohv0xg7op68j6fx8441mjczsob83.png)
When t=500 years:
![M(500)=100\cdot e^(-0.000436*500)](https://img.qammunity.org/2021/formulas/mathematics/college/5pcoh80ffya3ojlyx40a7fxqbe04uzuw2l.png)
![M(500)=100\cdot 0.804](https://img.qammunity.org/2021/formulas/mathematics/college/rk2r0cj5j229yn54gmssdd92dm0n9nflbt.png)
M(500)=80.4 gr
There will be left 80.4 of the sample in 500 years