203k views
3 votes
Write the equation for a line that passes through (5,-4) and is perpendicular to the

linear function 2x - 10y = 0

User Sherah
by
4.2k points

1 Answer

6 votes

Answer:

y = -5x -24

Explanation:

Given parameters:

Coordinates of the line = (5, - 4)

Linear function ;

2x - 10y = 0

Solution:

The equation of the line perpendicular to this line will have a slope that is the a negative inverse of the given line;

2x - 10y = 0

Equation of a line is given as;

y = mx + c

y and x are the coordinates

m is the slope

c is the y-intercept

We find the slope and y-intercept of the new line;

From: 2x - 10y = 0

Rewrite;

-10y = -2x

y =
(-2)/(-10)x

y =
(1)/(5)x

The slope of this line is
(1)/(5) , the line perpendicular will have slope of -5

For the new line;

y = mx + c

let us find c;

-4 = -5( -4) + c

-4 = 20 + c

c = -20 - 4

c = -24

The equation of the perpendicular line is;

y = -5x -24

User Nasreddin
by
4.1k points