Question

Find h(j+1) if h(x)=4x² + 3x - 2

Answer 1

h(j+1) = 4j² +11j +5

Explanation:

A function is evaluated for a specific argument by substituting that argument for the variable in the function's expression. Then the expression is simplified.

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For function ...

h(x) = 4x² +3x -2

The value of h(j+1) is ...

`h(j+1)=4(j+1)^2 +3(j+1)-2\\\\= (4(j+1)+3)(j+1)-2=(4j+7)(j+1)-2=4j^2+11j+7-2\\\\\boxed{h(j+1)=4j^2+11j+5}`