Question

How would I graph a line that contains the point (6,5) and has a slope of - 2/3 ?​

Answer 1

Y=-2/3x+5
Answer is

Answer 2

y=-2/3x+9

Explanation:

Use point-slope formula:

y-y1 = m(x-x1)

y-5=-2/3(x-6)

y-5=-2/3x+4

y=-2/3x+9

You would then proceed to graphing this equation, as it is in slope intercept form now.

HTH :)