Answer:
The probability that more than 5 parolees out of 15 that return to prison within 3 years is 0.2784.
Explanation:
The random variable X be the number of parolees that return to prison within 3 years.
The probability of occurrence of the random variable X is, p = 0.30.
A random sample of n = 15 prisoner are selected.
It is assumed that whether or not one prisoner returns to prison is independent of whether any of the others return to prison.
The random variable X follows a binomial distribution with parameters n = 15 and p = 0.30.
Compute the probability that more than 5 parolees out of 15 that return to prison within 3 years as follows:
![P(X>5)=1-P(X\leq 5)](https://img.qammunity.org/2021/formulas/mathematics/college/ssyvc32uryxmvkitsdzr0gb078u2cldgui.png)
![=1-\sum\limits^(5)_(0){{15\choose x}(0.30^(x)(1-0.30)^(15-x)}\\\\=1-[0.00475+0.03052+0.09156+0.17004+0.21862+0.20613]\\\\=0.27838\\\\\approx 0.2784](https://img.qammunity.org/2021/formulas/mathematics/college/zej8sv1av60skf9vp8lj3y8ix14qu3rg6b.png)
Thus, the probability that more than 5 parolees out of 15 that return to prison within 3 years is 0.2784.