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Solve the inequality. Define the solution set using numbers and symbols.


(x+17)/(x^2 +3) \geq 4

User Edeph
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1 Answer

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(x + 17) / (x ² + 3) ≥ 4

x + 17 ≥ 4 (x ² + 3)

4x ² - x - 5 ≤ 0

(4x - 5) (x + 1) ≤ 0

The left side is equal to 0 when either

4x - 5 = 0 or x + 1 = 0

x = 5/4 or x = -1

For x < -1, we have both x + 1 < 0 and 4x - 5 < 0, so their product is positive and there are no solutions to the inequality in this interval.

For -1 < x < 5/4, we have x + 1 > 0 and 4x - 5 < 0, so their product is negative.

For x > 5/4, we have both x + 1 > 0 and 4x - 5 > 0, giving a positive product and thus no additional solutions.

The solution set is then the second interval, but including the endpoints since that makes the expression on the left equal to 0:

-1 ≤ x ≤ 5/4

User Jordan Kowal
by
6.2k points
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