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2 votes
Find three consecutive integers such

that the sum of the first and the
second integer is three more than the
third integer.

1 Answer

6 votes

9514 1404 393

Answer:

4, 5, 6

Explanation:

Let x represent the middle one. Then the sum of the first two is ...

(x -1) +x

And we want that to be 3 more than the third:

(x -1) +x = (x +1) +3

2x = x +5 . . . . . . . . . add 1, simplify

x = 5 . . . . . . . . . . . . . subtract x

Since 5 is the middle integer, the three integers are ...

4, 5, 6

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