Question

PLEASE HELPPPP! HOW DO I DO THIS???

1. Calculate the amount of heat released when a 225 g sample of gold cools from 86.0oC to 32.5oC. The specific heat of gold is 0.129 J/goC


2. A 19.6 g sample of a metal was heated to 61.67oC. When it was placed into 26.7 g of water in a constant pressure calorimeter, the temperature of the water rose from 25.00oC to 30.00oC. Determine the specific heat of the metal if the specific heat of H2O(liq) is 4.18 J/goC. Ignore any contribution from the container.

Answer 1

1552.83J Released

Step-by-step explanation:

1. mass/m=225

Initial temp:86C, final:32.5C

Changed Temp: 32.5-86= -53.5C

s=0.129 J/gC

Formula: q= m times s times changed Temp.

q=(225)(0.129)(-53.5)

q= -1552.83 J

q=1552.83 J Released