Question

A plane flies at a steady rate of 40 mph while a second plane flies at a steady rate of 100 mph. The planes are 200 miles apart and fly directly toward each other. In how many hours will they meet?

plz help
times almost up

Answer 1

The time the two planes will meet is 1.43 hours

Explanation:

Given;

speed of the first plane in positive direction, = 40 mph

speed of the second plane in negative direction(opposite direction) = -100 mph

distance between the two planes = 200 miles

Let the time the two planes will meet = t

the position of the first plane at this time "t" = 40t

the position of the second plane at this time "t" = -100t

(40t)>--------------------------------<(-100t), this space between them is 200 miles.

Thus, the difference in the distance they traveled before meeting should be equal to 200 miles.

40t - (-100t) = 200

40t + 100t = 200

140t = 200

t = 200 / 140

t = 1.43 hours

Therefore, the time the two planes will meet is 1.43 hours