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In how many ways can a president, vice president, and secretary be chosen from a class of 20 girls and 30 boys if the president must be a girl and the vice president a boy?

User Mudshark
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1 Answer

2 votes

Given:

Number of girls = 20

Number of boys = 30

The president must be a girl and the vice president a boy

To find:

Number of ways to choose a president, vice president, and secretary.

Solution:

The president must be a girl and the vice president a boy. So, out of three students 1 is girl and 1 is boy. Third student can be a girl or a boy.

Total number of ways = Selecting 2 boys and 1 girl + Selecting 1 boy and 2 girls


=^(30)C_2* ^(20)C_1+^(30)C_1* ^(20)C_2


=(30!)/(2!(30-2)!)* (20!)/(1!(20-1)!)+(30!)/(1!(30-1)!)* (20!)/(2!(20-2)!)


=(30* 29* 28!)/(2* 1* 28!)* (20* 19!)/(19!)+(30* 29!)/(29!)* (20* 19* 18!)/(2* 1* 18!)


=(30* 29)/(2)* 20+20* (20* 19)/(2)


=8700+3800


=12500

Therefore, the required number of ways is 12500.

User Ywbaek
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