Question

A gas occupied 780.0 mL at a temperature of 30°C. Several days later, it was measured at

a temperature of 16°C.
What volume did the gas occupy under these new conditions?

Answer 1

744.0 mL

Step-by-step explanation:

Formula obtained from Charles Law :

⇒
`(V_(1) )/(T_(1) ) = (V_(2) )/(T_(2) )`

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Given :

⇒ V₁ = 780.0 mL

⇒ T₁ = 30 °C = 303 K

⇒ T₂ = 16 °C = 289 K

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Solving :

⇒ V₂ = 780 × 289 / 303

⇒ V₂ = 225420 / 303

⇒ V₂ = 744.0 mL (approximately)