Question

Which shows the equation of the line containing the point (–2, 6) and having a slope of 3 in slope-intercept form?

3y = x + 20


y=3x−20

y = 3x + 12


y=−32x+3

Answer 1

y=3x+12

Explanation:

Use this formula: y-y1=m(x-x1)
(y-Your y point=slope(x-Your x point)

Point= (-2, 6), Slope= 3

(Anything negative, you add. Anything positive, you subtract.)

Plug in your values: y-6=3(x+2)
distribute: y-6=3x+6
Add six to both sides of the equation:y-6(+6)=3x+6(+6)
We get our answer: y=3x+12
Hope this helps!! :)