Question

A falling object traveled can be moldeled by equation d= 1/2 at 2 where a is acceleration and t time fallen how do you finf t in terms of a and d ex. T= square 2d/a

Answer 1

`t = \sqrt{(2d)/(a)}`

Explanation:

Given

`d = (1)/(2)at^2`

Required

Solve for t

To do this, we simply make t the subject of formula;

This is done as follows:

`d = (1)/(2)at^2`

Multiply both sides by 2

`2 * d = (1)/(2)at^2 * 2`

`2d = at^2`

Divide both sides by 2

`(2d)/(a) = (at^2)/(a)`

`(2d)/(a) = t^2`

Take square root of both sides

`\sqrt{(2d)/(a)} = t`

Reorder

`t = \sqrt{(2d)/(a)}`