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Let h(t)=-16t^2+5t+1.What is h(1)?
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Let h(t)=-16t^2+5t+1.What is h(1)?

User Facewindu
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2 votes

Answer:

h(1)= -16(1)² +5(1) + 1 ==> -16+5+1 ==> -10

User Andre Liberty
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