Question

A moving electron accelerates at 5200 m/s^2 in a 55 degree direction. After 0.530 seconds, it has a velocity of 6598 m/s in a -20.5 degree direction. What is the y-component of the initial velocity?

Answer 1

-4568.25 m /s

Step-by-step explanation:

Consider all velocity in y direction .

Acceleration in y direction = 5200 sin55 = 4259.59 m /s²

y component of final velocity = - 6598 sin 20.5 = - 2310.67 m /s

Let y component of initial velocity be u

v = u + at

- 2310.67 = u + 4259.59 x .53

- 2310.67 = u + 2257.58

u = - 4568.25 m /s

So y component of initial velocity

= -4568.25 m /s