Answer:
1.66 kg
Step-by-step explanation:
Given that a 0.83-kg block is hung from and stretches a spring that is attached to the ceiling.
From Hook's law
F = Ke
But F = mg
Substitute mg for force in the Hook's law
Mg = ke
0.83 × 9.8 = ke
Make K the subject of formula
8.134 = Ke
K = 8.134 /e
Given that a second block is attached to the first one, and the amount that the spring stretches from its unstretched length triples.
That is
(0.83 + M) × 9.8 = K (3e)
Substitutes K into the above equation
(0.83 + M) × 9.8 = 8.134 / e (3e)
The e will cancel out
(0.83 + M) × 9.8 = 24.402
0.83 + M = 24.402/9.8
0.83 + M = 2.49
M = 2.49 - 0.83
M = 1.66 kg
Therefore, the mass of the second block is 1.66kg